Triangle Partitioning

Time Limit: 0.5 second(s)

Memory Limit: 32 MB

See the picture below.

 

You are given AB, AC and BC. DE is parallel to BC. You are also given the area ratio between ADE and BDEC. You have to find the value of AD.

Input

Input starts with an integer T (≤ 25), denoting the number of test cases.

Each case begins with four real numbers denoting AB, AC, BC and the ratio of ADE and BDEC (ADE / BDEC). You can safely assume that the given triangle is a valid triangle with positive area.

Output

For each case of input you have to print the case number and AD. Errors less than 10^-6 will be ignored.

Sample Input	Output for Sample Input
4 100 100 100 2 10 12 14 1 7 8 9 10 8.134 9.098 7.123 5.10	Case 1: 81.6496580 Case 2: 7.07106781 Case 3: 6.6742381247 Case 4: 7.437454786

 

简直就是大神们秀智商的天堂。

#include 
      
        #include 
       
        int main(){    int t, Tim = 1;    scanf("%d", &t);    while(t--){        double a, b, c, d;        scanf("%lf%lf%lf%lf", &a, &b, &c, &d);        double temp = sqrt(d/(d+1));        printf("Case %d: %.6lf\n", Tim++, temp*a);    }    return 0;}